This is an idea that’s kinda similar to Thue-Morse Go, in that it makes the game more “fair” (with a definite reduction in komi requirement, and possibly reduced to 0), and can involve weird passes.
Ok, so imagine you have two go boards, but you only have one move to play between them, and the score for the total game is the combined score of both of the boards.
If the boards are the same size this is necessarily fair because any move b makes can be copied b w on the other board, creating two identical and opposite games.
Now, naturally it’s kinda boring if there’s a known (and simple) way to force a draw (unless you’re a better player trying to show your opponent when they play slow moves),
so clearly there has to be something to prevent that from happening, either each board has to have two different (but relatively equal-value) positions
Play it across two sizes.
Naturally the game will likely not be a guaranteed forced tie, but it would make it certainly very close and only require small bits of komi, while providing interesting possibilities.
For example these are the two boards of a game of this I played against jmdingess on a 9x9 and 13x13 board
on the 9x9 I lost by 83.5 (78 ignoring komi cuz jimmy got it twice)
and on the 13x13 I won by 58.5 (64 ignoring komi)
therefore I lost by 14 points (and I was lucky to get that close)
Unfortunately this doesn’t preserve moves between two boards, so this isn’t necessarily a complete record of the game, but you might notice some weird passes, and those are intentional: the player passing had tenukid to the other board and the other player eventually got sente (or thought they had it) to play back on that board.
But I think it allows for weird positions the same as Thue-Morse, but isn’t quite as strange to do live (and is even better in person as you don’t have pesky clocks and tab switching in the way)
and also is guaranteed to be more fair than a no-komi game, although black still probably has a slight (probably 1 or fractional-point) advantage
EDIT: apparently it’s not guaranteed, but it is likely to by of the form x-y (although this has an upper error bound of 2y, which would be the same as x+y)