Tsumego 57: Black to kill
For the previous problem, see the solution here.
It seems like you can make a ko, but how should you go about it?
For the previous problem, see the solution here.
Seems the link to the previous problem is wrong (pointing to the second to last one).
Thanks for pointing out. I copy and pasted without updating.
It seems that white has played at the vital point, and the two cuts are miai. What can black do?
For the previous problem, see the solution here.
Black F1 β White G2 β Black G1 β White J1β¦ doesnβt work.
Black F1 β White G2 β Black H1 β White G1β¦ doesnβt work.
Black G2 β White E2 β Black C1 β White A2 β Black F3 β White A1 atariβ¦ doesnβt work.
Black G2 β White E2 β Black D1 β White E1 atari β Black F3 atari β White C1 captureβ¦ doesnβt work.
Black G2 β White E2 β Black E1 β White F1 atari? β Black F3 atari β White D1 capture + atari β Black G1 atari β White C1 capture β Black J1 makes 2 eyes. ![]()
If White C1 throw-in + atari instead of F1 atari one stone, Black will capture at D1 first, then White atari at F1 β Black atari at F3 β White capture at C1 β Black plays G1 β White must defend at D2 β Black J1 and makes 2 eyes.
Proud of myself of getting this without playing it out on a goban, took me about 20 minutes. I wonder what rank it would be on goproblems.com .
Whatβs the best result black can achieve?
For the previous problem, see the solution here.
after recapturing with bA3, wB3 wC3, bA1, a step ko?
B4 - A4 - A2 - A1 A3 ?
The problem is what happens after that
The best result here might be to resign and save time, go cook dinner or something more productive. Too demoralizing to try to live there (two-step disadvantage ko)
Black B4 β White A4 β Black A2 β White A1 β Black A3 β White A2 β Black A3 β White B3 β Black B2
β White C3 β Black A1 β White C2 β Black C1 β White takes ko β Black needs to win the ko 2 times to capture the 3 stones and live