Thanks, but I STILL don’t get it … here B already HAS two eyes:
@trohde this post (the one I’m replying to) is what started this exchange. Its context is a Sensei’s Library page discussing pass-alive groups and images illustrating Benson’s Algorithm, which is why they’re the relevant concerns here and not just eyes in general
If you let white play 4 times without black answering, white can capture black.
Try it.
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but HOW should W play 4 times if suicide is not allowed? I only see a possible maximum of 3 times.
Key is that white doesn’t play at Q19 (or F9 on the 9x9), but keeps it open as a liberty for it’s own stones. As fourth move white plays the 1-1 and takes away black’s last liberty.
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Maybe my mind is going.
Please show me how that is supposed to work:
White can play at 4 last, because he is capturing (last black liberty)
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Oh &§$#%! … OK, this seems SO stupid to overlook that I simply couldn’t imagine.
Thanks all for your patience.
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it is not unconditionally alive by beson. benson says the the opponet nerver has to answer.
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