I shall try to sketch out a thought process that leads you to the answer. If you can follow it, it should help, if not, you need to review some more elementary techniques.
Here is the original puzzle:
We need to trim that to manageable proportions. We think where White must play to complete their outside border, if Black answers any attempts to expand it. In the long run the largest they can make it is occupying A, B, and C. (They could try tricks like jumping to D, but the will not make room for eyes, and in the end will have to come back to C. Similarly they can push at E, but will have to play A in the end.)
Here the blue line is crucial, as it shows those spots where White has a chance to build eyes; the Black line around the outside of White’s wall is not really important.
So we can narrow the area we look at down to this:
We have already reduced our search tree considerably: 5! = 120, which sounds doable, with some effort.
Now we think what White could do to make two eyes in there. If you are familiar with nakade shapes you should see at once that Black could kill by occupying these two spots:
Your can also find these spots by seeing that they are the central ones, that connect the others. They have two and three vacant neighbours respectively; the rest have only one.
So White must get one of those spots to live. The resulting shapes are
and
We now go back to the original shape, thus reduced:
Before going further, let me add that in most Life & Death problems we have to choose between reducing/enlarging eyespace from the outside and playing a vital point in the middle of it. Here we have been given a hint, “Play the vital point”.
We now think what happens if Black takes one of the vital points. The more promising seems to be the 3-1 points, as it has more vacant neighbours:
Most of White’s eyespace has been fused into a single eye, and to get another White may try to block at 2 here:
But then Black can play 3, and White can only make a false eye. If White played 2 at A it would not help, and 2 at 3 would be answered by Black at 2. So this black 1 is a success.
But we should perhaps consider Black’s other option, which might turn out better in some way:
Again, White takes the other of the two central points:
This time White lives: they can not be stopped from occupying A, and
x and
y are
miai, meaning that whichever Black plays, White is fine if they play the other.