If anyone wants to spectate:
This was the order the stones were placed in:

(odd stones placed by Tschej, after 9 I decided to play as black)
If anyone wants to spectate:
This was the order the stones were placed in:

(odd stones placed by Tschej, after 9 I decided to play as black)

(odd stones placed by me, after 9 fuseki3 decided to play as black)
Anyone interested in some matches?
I realized after my last matches that I prefer live games, but Id be down for correspondence as well!
I am always up for a Kill-All game on 19x19. Happy to play either White or Black. Any rank is fine. Iβm about 4 kyu but my life and death is probably closer to 6 kyu level.
Send me a message here / challenge on OGS.
Hey are you intrested in playing again?
Iβm pretty busy right now, sorry
anyone interested in 9x9 kill-all go?
β
β
β
We could do either
β
β
You play black, you put up to 4 of your stones on the board, and then itβs my turn.
or
Black starts with up to 5 stones, using a partial pie rule.
My original attempt at describing this was too restrictive;
I have a corrected description two posts down.
β
β
.
Im interested. Living with 4+ stones on the 9x9 sounds very hard. But I surely like to give it a try.
In β 9x9 Kill-All Go , β Tschej played black and placed
4 black stones, after which it became my turn.
β
β
β
9x9 Kill-All Go was β Black starts with up to 5 stones, using a partial pie rule
(0) β β β One player chooses a number n from β {0,1,2,3,4,5} β .
(1) β β β The other player chooses who chooses the intersections for (2).
(2) β β β The player determined by (1) chooses up to n intersections.
(3) β β β The other player chooses colors.
(4) β β β Black places stones at the intersections chosen for (2),
β β β β β β β β and up to 5-n more stones, after which it is Whiteβs turn.
, β where since I came up with the above, I specified
If I make the choice for (0), then my choice is n = 3 .
If Tschej chooses n < 3 then my choice is that Tschej chooses the intersections for (2).
If Tschej chooses n > 3 then my choice is that I choose the intersections for (2).
If Tschej chooses n = 3 then I let Tschej make my step-(2) choice for me.
.
β
β
Tschej went with β β β n = 3 β and β I choose the intersections
, β β β β β β β and the intersections I chose were β β β B2 , B3 , C7 β .
Anyone interested?
Live or correspondence is both fine with me.