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Reminder @Tschej
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Reminder @Sadaharu
So if @Jon_Ko keeps playing C10, which threatens to capture C11, and @PRHG keeps playing C10 to prevent capture, then the two are cancelling each others moves.
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Reminder @Tschej
@garlicsoup I believe that connecting the white groups at the top is important, and I am happy that we get the chance to do so. Shall we coordinate our moves to prevent that we collide?
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Iâll play H2.
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Thank you, then I will play somewhere else.
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Round 13
This time Iâm not 100% sure what happened 
Though it seems plausible that @Jon_Ko 
and @PRHG 
played at C10 again. This implies that @Tschej 
played at D5, which results in the capture of the brown chain. @JohnnieDarko 
could have played C10 or D5 (though D5 seems more plausible to me).
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I indeed played D5 and captured Tschejâs E5.
I donât understand why my D5 stone is gone though, it is fully connected to my D6 stone so it couldnât be captured. Well obviously it could, but not in my understanding of the rules
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Tschej played D5, so the D5 stone would have been red, green, black and white. This means D5 would have been part of the red group comprised of D5 and E5. This red group had no liberties, and was thus removed from the board. At least this is my best explanation.
I think it doesnât matter if your stone is part of a group that wouldnât be captured, as long as itâs part of a group that does get captured then it gets captured.
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Thanks! lightbulb moment here.
I expected that first my D5 would capture E5, (because captures are resolved first in go), and then Tschejâs D5 would combine with mine to form that four color stone.
But the order of things is then: stones are placed at the same time, and then captures are resolved. (I think).
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Can confirm this, and your explanation is sound.
Your interpretation of normal go rules is interesting to me - the idea that captures are resolved first and then the stone is placed.
Iâve always thought of it in this order - first stone placement, then resolve captures of opponents stones, then check for self capture.
Yes, you can think of it as three steps:
1.) stones are placed at the same time
2.) old chains without liberties are removed
3.) new chains without liberties are removed
⌠where chains are called ânewâ if they contain a stone placed this round, otherwise âoldâ.
So if the stone placed at D5 was only white-green, then the capture would have occurred as you expect.
We can take black-greens capture at D9 as another example. After placing the stone, the black chain has no liberties, but since E9 is an old chain that gets removed in step 2., D9 survives.
This is where it works intuitively, in my opinion. Needless to say, there are many unintuitive examples as well
I believe the whole idea goes back to Diplomatic Go
Note that this mechanism is compatible with normal go rules - here all opponents chains are âoldâ, and self capture can only occur for the chain containing the newly placed stone, i.e. a ânewâ chain.
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âInterestingâ 
Yeah itâs a lazy shortcut of the rules, your reading makes more sense.
This clears it up. I read this before but forgot about it.
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I think it would be interesting to have something analogous to ko, where if two or more players play a single stone on the same space, and that one stone dies, but no other stones are captured because of it, then those players cannot play on that same space next turn.
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@PRHG do you want to break the stalemate on D10? I can start removing liberties from @Jon_Ko s stone.
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Yeah sure, if you donât feel the immediate need to play elsewhere
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