The reason why I changed my mind:
… but it seems I saved black… sorry…
The reason why I changed my mind:
… but it seems I saved black… sorry…
If there was a stone at T5, would black+green R5 be suicide? (Also, is suicide legal in this variant?)
I think this is the most fun Ive ever had playing go (Keep in mind 99 % of my time with go is spent watching AGA and dwryin videos, and watching Kata play itself, lol)
That’s what I was thinking and it would have been good for black, the current position is okay for white I think.
No, captures of “old” groups have priority over captures of “new” groups, so R5 would be captured first, giving Black|Green a liberty
Are you sure?
Yes:
Exactly, R5 would be new, so the four green+black are a green chain with a “recently placed stone”. They would be removed in step 2. Unless T5 would be green too, then T6 would be a liberty for green.
Ah, wait, yes, I had S5 in my mind, and that it was about last move, never mind.
Yes it is allowed. This can be very important because chains can include stones of both sides, so tactical suicide is a thing.
A more profound reason is, I do not know how to formulate a rule disallowing suicide in this variant Because of the simultaneous moves, before placement of all stones is revealed, it is often unsure if a move will result in one of the connected chains to be captured.
I’m thinking that @terrific and @yebellz can handle the green threat in the lower-right. So I’ll work on getting my four eyes by playing S17.
I don’t have the time to do the update right now, but I’ll do it shortly.
Sorry for the delay.
Round 9
Team | Blue | Green | Pink |
---|---|---|---|
Black | @Maharani: K15 | @Jon_Ko: O3 | @Vsotvep: S15 |
White | @yebellz: T5 | @Feijoa: P5 | @terrific: N3 |
New Position:
Deadline for Round 10: 2021-11-28T09:00:00Z
In my role as asker of stupid questions, let me enquire:
If white+green plays at Q6 and black+green plays at R5, and no one else plays locally, which (if any) stones are removed from the board?
This seems like a question to understand the rules better, so I’ll answer: That would result in two chains having no liberties: The light-blue chain containing the stones Q4 and Q5, and the green chain containing the stones R4, R5, S4 and S5. Of these two, the light-blue chain contains no stones that were just placed, so it gets removed first, which frees up liberties of the green chain, which is thus not removed.
Let’s say that
a) White+green plays at Q6,
b) White+red plays at R7, and
c) Black+green and black+blue collide at R5.
What happens…?
(Edited)
The same green chain and a light-blue chain that is slightly larger than in the last example both have no liberties and are simultaneously removed, because both contain a “recently placed stone”.
→
I really must go to sleep now, good night!
Would love to hear everyone’s thoughts on the bottom-right situation!
I was thinking team white should play at R6 and Q5 Q6 and R5 to kill four stones, should I play one of those?
I definitely approve of team white submitting two illegal moves
To me it seems like white was really successful there, although we started with a good position.
The corner is gone IMO, the right side needs fortification. I wonder if I can help with the attack on the upper right.