I think that multiple URLs will produce the same board position, however, I would guess that given a board position (and static player names), the tool would always generate the same URL via the link button.
On a Linux command line, the sort and uniq tools would make it easy to find duplicates in a list of strings.
I think it parses the moves from top right to bottom left, so clicking the link button should give a unique link.
Yes.
Every stone is composed of three letters, and in encoding the board it doesnāt check if the input is also given from top left to bottom right, so you can get multiple links to the same position. But clicking the link will always produce the same result.
So, assuming the urls were all generated using the ālinkā button, and assuming the urls are listed one per line in a text file positions.txt, then on Unix, sort positions.txt | uniq -d should output all the repeated positions (and will have no output if there are no repeated positions).
I kind of doubt weāll get repeating positions. 
Iām prepared to repeatedly play N6.
Round 87
| Team | Blue | Green | Pink |
|---|---|---|---|
| Black | @Maharani: R8 | @Jon_Ko: H1 | @Vsotvep: R1 |
| White | @yebellz: N5 | @Feijoa: H1 | @terrific: F4 |
Feijoa and Jon_Ko collide at H1. Placing all stones ā¦
ā¦ H1, S8 and the green chain connected to N6 get removed. New Position:
Check-in Time for Round 88: 2022-06-11T17:00:00Z
Weāre back to the same problem of connecting the Black chain through N6 / N7.
Instead of @Jon_Ko, I could use this turn to be the other move of those two stones that @Maharani doesnāt play, in case H1 is more important than anything I do with the pink group.
Currently the green group has 5 liberties, and the pink group 6, and they share two of them. Itās still pretty much up for grabs.
I will play N6, then.
I donāt think H1 is that important. It gives one liberty to green, but @Vsotvep you could also take away one liberty from pink, and that might work better than H1.
I still think I should play N6, @Maharani, because my N7 would immediately die even without white interference. For green N6 to die, white would still need to invest a stone.
Iām counting 4 for green.
Okay, Iāll play N7
But the goal is for Green to die and it becoming solidly Blue | Black (| White) at some point.
The reason to play a Green stone is to prevent the intersection from becoming solidly Blue | White, since we canāt connect our Black stones like that anymore, which would be a major loss (probably game-deciding).
In general, I agree. But as long as thereās a black stone, black is connected. The stone doesnāt have to be blue.
Sure, team white can kill the stone if itās green, but whenever they use one stone to take our N6 off, weāll use one stone to play it again.
Exactly, but eventually Iām hoping the stone will only have the colour Blue, so that we can free up the moves to spend them elsewhere. As long as itās Black itās connected, so we cannot be disconnected by force or chance. But, we also have to keep the connection up to date every time itās removed.
Yes, if I (or you) play N6. If I (or you) play N7, N7 will die right away without team white having to remove it and we have to keep the connection up to date anyway. So making white invest a stone seems better to me.
I guess Iām playing ā¦ N6 then 
Round 89
| Team | Blue | Green | Pink |
|---|---|---|---|
| Black | @Maharani: N7 | @Jon_Ko: N6 | @Vsotvep: Q5 |
| White | @yebellz: N7 | @Feijoa: N7 | @terrific: Q5 |
Maharani, yebellz and Feijoa collide at N7, Vsotvep and terrific collide at Q5! After placing all (combined) stones ā¦
ā¦ N5 is removed, freeing up liberties for the new green chain connected to N6. New Position:
Check-in Time for Round 90: 2022-06-13T19:00:00Z
I have started a .txt file where Iāll gather the URLs for future reference, starting with this round.
By the way, I noticed last round that weāre off in the round numbering again. This one we just played was round 89
ups, thank you for pointing it out.
And round 88 is called round 87 
Yeah I decided to leave it as an easter egg
